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Q: What is the product of 7y3 and 4y5?
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It is: 12y^7


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It looks like the first half of an equation. If the full equation is "3y-7y^3=0" then you would need to solve for "y". add 7y^3 to both sides divide both sides by y divide both sides by 7 You get 3/7 = y^2 take the square-root of both sides to get y = sqrt(3/7) or approximately 0.654


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