The third multiple of 3 is 9 and the fourth multiple of 4 is 16. So 9 multiplied by 16 is 144.
15 is. Intriguingly, it's also the 3rd multiple of 5.
Because each of the numbers is a multiple of 3, so their product will be a multiple of 3 x 3 = 9. Algebraically: let the two numbers from the 3 times table be 3m and 3n for some m and n. Their product is 3m x 3n = (3 x 3)mn = 9mn, a multiple of 9.
The product is the result of multiplying two or more numbers.In the calculation 3 x 5 = 153 is the multiplicand and 5 is the multiplier. Both of them are factors, and 15 is the product. 15 is also referred to as a multiple of the numbers - 15 is a multiple of 3, and 15 is a multiple of 5.
It's not. 3 is a factor of 6. 6 is a multiple of 3.
The LCM of 3 and 47 is 141.
The fourth positive multiple of 3 is 12.
Yay! i answerd first
The fourth Fibonacci number is 3, so the only possible answer is "3". It does indeed look as if every fourth number after that is a multiple of 3.
15 is. Intriguingly, it's also the 3rd multiple of 5.
There was no product known as the iPad 3. The 3rd generation iPad was known as the 'new iPad'. The fourth generation iPad will also be known as the 'new iPad'.
81 3x3x3x3=81
Because each of the numbers is a multiple of 3, so their product will be a multiple of 3 x 3 = 9. Algebraically: let the two numbers from the 3 times table be 3m and 3n for some m and n. Their product is 3m x 3n = (3 x 3)mn = 9mn, a multiple of 9.
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