7
replace 7 with x: x+2x=3x x+2x+3x=6x all ten of them -> 55x Put the 7 back in: 55(7)=385 OR: The first ten multiples of 7 are 7,14,21,28,35,42,49,56,63,70 The product of the multiples will then be 7+14+21+28+35+42+49+56+63+70= 385 :)
These are the first 90 multiples of 7:714212835424956637077849198105112119126133140147154161168175182189196203210217224231238245152159266273280287294301308315322329336343350357364371378385392399406413420427434441448455462469476483490497504511518525532539546553560567574581588595602609616623630
The first 3 multiples of 7 are: 7, 14, and 21.
The first 6 multiples of 7 are: 7, 14, 21, 28, 35, and 42.
7
The product is 5x10x15x20x25 = 375000
Since 4 divides 12, they are the first 7 multiples of 12.
seventy two
21,42 and 63 are the first three multiples
The common multiples of an set of numbers are the multiples of their lowest common multiple. lcm(7, 8, 9) = 504 → the first 3 common multiples of 7, 8, 9 are 504, 1008, 1512.
7,14,21,28,35
7,14,21,28,35,42,49