#include
bool is_prime(unsigned num)
{
// 2 is the first prime and the only even prime.
if (num < 2) return false;
if (num == 2) return true;
if (num % 2 == 0) return false;
// Divide num by every odd number from 3 up
// to and including the square root of num.
// If any division results in no remainder
// then num is not prime.
unsigned max = sqrt ((double) num) + 1;
unsigned div = 3;
do {
if (num % div == 0)
return false;
} while ((div += 2) < max);
// If we get this far, num is prime.
return true;
}
int main()
{
std::cout << "Prime numbers in the range 0 to 300:\n" << std::endl;
unsigned num = 0;
do {
if (is_prime (num))
std::cout << '\t' << num << std::endl;
} while( num++ < 300);
std::cout << std::endl;
}
Example Output
Prime numbers in the range 0 to 300:
2
5
7
11
13
17
19
23
29
31
37
41
43
47
53
59
61
67
71
73
79
83
89
97
101
103
107
109
113
127
131
137
139
149
151
157
163
167
173
179
181
191
193
197
199
211
223
227
229
233
239
241
251
257
263
269
271
277
281
283
293
how to write a program that counts automorphic number from 1 to 999
The A Plus Program is an initiative, not a test. So no, there is no answer book.
#includeint main(){int i;for(i=2;i
#include<iostream> int main() { int i=0; while(i++<10) std::cout<<i*i<<std::endl; }
++a (plus plus a) is pre-incrementing operator to aa=10;printf("%d",++a); /* it will print 11 as ++a increment first a by 1 then prints it */printf("%d",a++); /*it will printf 10 as it is post _ increment operator , it prints the value a first then increment it by 1 */
By learning how to program on C+.
a prime number is a number that you can plus by one
It is: (x+1)(x+4) none of which are prime numbers
how to write a program that counts automorphic number from 1 to 999
127 prime numbers in that range. See related link for prime numbers up to 10000. Plus there is a link to download Zip files of prime numbers up to 1 million.
NO!!!! Other than '2' all prime numbers are odd numbers. 4,6,10 & 20 are all even so they are not prime numbers.
#include using std::cout;using std::endl;int main(viod){cout
It would always be a natural number.
19 plus 79
They are 23 plus 7 = 30
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p7# - 1 = 510509 and p7# + 1 = 510511, neither of which is prime.