(x - 3)(x + 1)
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
In the generic formula, replace the coefficients a = 1, b = -2, c = -3.
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
Write it as x2 - 2x - 4 = 0, and solve with the quadratic formula (a = 1, b = -2, c = -4).
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
x = 7/2 and also x = -3/2 by using the quadratic equation formula.
x2 + 2x + 2 = 0 Use the quadratic formula: x = (-2 +- sqrt(4 - 8))/2 x = (-2 +- 2i)/2 = -1 +- i
Using the quadratic formula, you get the complex answers of 1 + 2i and 1 - 2i
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
Using the quadratic equation formula:- x = 1 +/- the sqrt of 13 = -2.60555 and 4.60555 (to 5 dp).
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0
If x2 + 5 = -2x, then x2 + 2x + 5 = 0 This equation cannot be readily factored so using the quadratic formula :- x= {-2 ± √[(-2)2 - 4x5]} ÷ 2 = {-2 ±√-16} ÷ 2 = -1 ± 2i Therefore x = -1 + 2i or x = -1 - 2i