3
y -3 = 9 y = 9+3 y = 12
To find two numbers that have a sum of 60 and a quotient of 4, let’s denote the numbers as ( x ) and ( y ), where ( x > y ). From the conditions, we have the equations ( x + y = 60 ) and ( \frac{x}{y} = 4 ). Solving these, we find ( x = 48 ) and ( y = 12 ). Thus, the two numbers are 48 and 12.
9 and 3 because 9+3 =12 and 9/3 = 3
9 and 3
12+3(y) 12+ 3(-3) 12 + {3x (-3)} 12+ (-9) 12-9 3
The Quotient of y and -2 is greater than 8
12/9 = 1.333 . . .
y/12 + 8 = 2
-9
y -3 = 9 y = 9+3 y = 12
To find two numbers that have a sum of 60 and a quotient of 4, let’s denote the numbers as ( x ) and ( y ), where ( x > y ). From the conditions, we have the equations ( x + y = 60 ) and ( \frac{x}{y} = 4 ). Solving these, we find ( x = 48 ) and ( y = 12 ). Thus, the two numbers are 48 and 12.
9 and 3 because 9+3 =12 and 9/3 = 3
How about 9 and 3 because 9+3 = 12 and 9/3 = 3
The quotient of two numbers, X and Y, is X/Y.
27/3 = 9
72/8 = 9
To find the two numbers that have a difference of 9 and a quotient of 2, we can set up a system of equations. Let's call the larger number x and the smaller number y. We have the equations x - y = 9 and x / y = 2. By solving these equations simultaneously, we can find that the larger number is 6 and the smaller number is 3.