To find the two numbers that have a difference of 9 and a quotient of 2, we can set up a system of equations. Let's call the larger number x and the smaller number y. We have the equations x - y = 9 and x / y = 2. By solving these equations simultaneously, we can find that the larger number is 6 and the smaller number is 3.
9/(x-5) is.
14 and 2
The Quotient of y and -2 is greater than 8
The quotient of 18 and 2 is 9 The sum of 22 and 9 is 31 31-9=22
18/2 = 9
2!!
quotient means to divide, so the quotient of 2 is to divide by 2. difference means to subtract, so subtract by 5
9/(x-5) is.
14 and 2
The Quotient of y and -2 is greater than 8
It is 2 times (738-280) plus 2466/9 = 1190
The difference between 6 and -2 is 8. The quotient 20/8 = 2.5
None. If the two numbers have a quotient of 9 then one of them must be 9 times as large as the other. In that case, their difference cannot be 0.
The quotient of 18 and 2 is 9 The sum of 22 and 9 is 31 31-9=22
18/2 = 9
63/7 = 9 63 - 7 = 56 The two numbers are therefore 7 and 63.
16/(9 + 7) = 1