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What is the radius and center of the circle of 100x squared plus 100y squared minus 120x plus 100y minus 39 showing work?
The general equation of a circle centre (a,b) and radius is (x-a)2+(y-b)2 = r2
Divide all terms by a 100 and rearange as follows:
x2-1.2x+y2+y-0.39 = 0
Complete the square in terms of x and y:
(x-0.6)2+(y+0.5)2-0.36-0.25-0.39 = 0
(x-0.6)2+(x+0.5)2 = 12
So its radius is 1 and its centre is at (0.6, -0.5)
What else can I help you with?
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A radius squared fits pi times into a circle (The area of a circle divided by pi is the radius squared).
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The radius is the line from the center of a circle to its circumference.
