There is nothing in the question which indicates any sort of relationship between the first cone and the second. Consequently, the question has no sensible answer.
The volume of a cone with radius of 4 and perpendicular height of 10 is: 168 cubic units.
A right circular cone with 8 height and 6 radius has a slant height of 10.
Volume = 261.8 (261.79939) units3
The smaller to the larger is a ratio of 6:10 or 3:5
The volume of a cone whose base has a radius of 8cm and whose height is 10 cm is: 670cm3
A cone that has a radius of 8 centimeters and a height of 10 centimeters can hold: 670.2 cubic cm of water.
Volume = 261.79939 units3
V = 1,361.4 cubic inches.
Without another piece of information, the radius alone isn't enough to tell you the volume of the cone. You really need the height too.
It will depend upon the radius of the base and as such will be any value between 0 cm3 and approx 403.067 cm3. The height and radius are linked by: radius2 + height2 = slant_height2 Volume cone = 1/3π x radius2 x height When radius is 0 cm, height is 10 cm and volume is 0 cm3 When radius is 10 cm, height is 0 cm and volume is 0 cm3 When radius is √(200/3) cm ≈ 8.165 cm and the height is √(100/3) cm ≈ 5.774 cm, the volume is at its maximum of 1/3π200/3√(100/3) cm3 ≈ 403.067cm3
V = 2,617.99 ft3
If two shapes are similar, then each length is in the same ratio. The ratio of the heights is 10 : 2 Thus the radii are in the same ratio, ie 4 : x = 10 : 2 → x = 2 × 4 ÷ 10 = 0.8 units