There is nothing in the question which indicates any sort of relationship between the first cone and the second. Consequently, the question has no sensible answer.
The volume of a cone with radius of 4 and perpendicular height of 10 is: 168 cubic units.
A right circular cone with 8 height and 6 radius has a slant height of 10.
Volume = 261.8 (261.79939) units3
The smaller to the larger is a ratio of 6:10 or 3:5
The volume of a cone whose base has a radius of 8cm and whose height is 10 cm is: 670cm3
Volume = 261.79939 units3
V = 1,361.4 cubic inches.
Without another piece of information, the radius alone isn't enough to tell you the volume of the cone. You really need the height too.
The volume of a cone is given by the formula V = 1/3 * π * r^2 * h, where r is the radius and h is the height. Plugging in the values, V = 1/3 * π * 8^2 * 10 = 670.8 cubic centimeters. Therefore, the cone can hold approximately 670.8 cubic centimeters of water.
V = 2,617.99 ft3
It will depend upon the radius of the base and as such will be any value between 0 cm3 and approx 403.067 cm3. The height and radius are linked by: radius2 + height2 = slant_height2 Volume cone = 1/3π x radius2 x height When radius is 0 cm, height is 10 cm and volume is 0 cm3 When radius is 10 cm, height is 0 cm and volume is 0 cm3 When radius is √(200/3) cm ≈ 8.165 cm and the height is √(100/3) cm ≈ 5.774 cm, the volume is at its maximum of 1/3π200/3√(100/3) cm3 ≈ 403.067cm3
If two shapes are similar, then each length is in the same ratio. The ratio of the heights is 10 : 2 Thus the radii are in the same ratio, ie 4 : x = 10 : 2 → x = 2 × 4 ÷ 10 = 0.8 units