11
Range = Maximum - Minimum = 13 - 2 = 11
Range = Max(set) - Min(set) = 13 - 2 = 11
the range for 5 2 1 and 3 is 4.
2 3/5 ÷ 5 = (2×5+3)/5 ÷ 5/1 = 13/5 ÷ 5/1 = 13/5 × 1/5 = (13×1)/(5×5) = 13/25
3 bcause 5-2=3
8 1+2 = 3 2+3 = 5 3+5 = 8 5+8 = 13 8+13 = 21
2 and 3/5 = 13/5
5-2=3
The range is {-3, 2, 0}.
52/3 = 17/3 So the reciprocal is 3/17
The equation:3 x 2 + 5 x 2 - 13 - 10 / 2= (3 x 2) + (5 x 2) - 13 - (10 / 2)= 6 + 10 - 13 - 5= -2
The range is 3.