In simple Python code: def convertToAngle(num): while True: if num < 0: num = 360 - num elif num > 360: num -= 360 else: break return num
371 over 1000 = 371 divided by 1000 = 0.371
120/371 * 100 = 32.345%.
# include <stdio.h> void Rec_Dec_To_Bin (int num); void main () { int num; int base; printf ("Enter the decimal number to convert it binary.\n"); scanf ("%d", &num); printf ("The number in decimal is : %d\n", num); printf ("\n"); printf ("The %d in binary is : ", num); Rec_Dec_To_Bin (num); printf ("\n\n"); } void Rec_Dec_To_Bin (int num) { if (((num / 2) != 0) && (num > 1)) { Rec_Dec_To_Bin ((num / 2)); } printf ("%d", (num % 2)); }
371/24 = 15.46 so there are about 15 and a half days in 371 hours.
yes
unsigned binary_to_gray (unsigned num) { return num ^ (num >> 1); } unsigned gray_to_binary (unsigned num) { /* note: assumes num is no more than 32-bits in length */ num ^= (num >> 16); num ^= (num >> 8); num ^= (num >> 4); num ^= (num >> 2); num ^= (num >> 1); return num ; }
spell check you'r answer
How about: 7*53 = 371 or 1*371 = 371
As a fraction .371 = 371/1000
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371.
In simple Python code: def convertToAngle(num): while True: if num < 0: num = 360 - num elif num > 360: num -= 360 else: break return num
371 is divisible by 1, 7, 53, 371.
#include<iostream> #include<sstream> #include<exception> std::string decimal_to_roman (unsigned num) { std::stringstream ss {}; while (num>0) { if (num>10000) throw std::range_error ( "ERROR: decimal_to_roman (unsigned num) [num is out of range]"); else if (num==10000) { ss<<"[M]"; num-=10000; } else if (num>=9000) { ss<<"[CM]"; num-=9000; } else if (num>=5000) { ss<<"[D]"; num-=5000; } else if (num>=4000) { ss<<"[CD]"; num-=4000; } else if (num>=1000) { ss<<"M"; num-=1000; } else if (num>=900) { ss<<"CM"; num-=900; } else if (num>=500) { ss<<"D"; num-=500; } else if (num>=400) { ss<<"CD"; num-=400; } else if (num>=100) { ss<<"C"; num-=100; } else if (num>=90) { ss<<"XC"; num-=90; } else if (num>=50) { ss<<"L"; num-=50; } else if (num>=40) { ss<<"XL"; num-=40; } else if (num>=10) { ss<<"X"; num-=10; } else if (num==9) { ss<<"IX"; num-=9; } else if (num>=5) { ss<<"V"; num-=5; } else if (num==4) { ss<<"IV"; num-=4; } else if (num>=1) { ss<<"I"; num-=1; } } return ss.str(); } int main (void) { for (unsigned n=1; n<=10000; ++n) { try { std::cout << n << "\t = " << decimal_to_roman(n) << std::endl; } catch (std::range_error& e) { std::cerr<<e.what()<<std::endl; break; } } }
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