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If the question is about
the remainder for 2x4 + 5x3 - 17x2 - 5 divided by x + 3
by the remainder theorem, to get the answer you first find the value of x tha t makes x + 3 = 0. That is x = -3.
You then substitute this value in the "numerator" expression:
Thus remainder = 2*(-3)4 + 5*(-3)3 - 17*(-3)2 - 5
= 2*81 - 5*27 - 17*9 - 5 = -131
Quotient: 2x3-x2-14x+42 Remainder: -131 over (x+3)
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
4705.341 because 5x3=15x556=8340 divided by the square root of pi(1.7724539) is4705.314.
15 5x3 prime factorization: 5x3
None. 5x3 is a pure number, not a length.
What is the additive inverse of the polynomial –9xy2 + 6x2y – 5x3?
The answer is 21
In the future, ask four questions as four separate questions to limit confusion. 6x7y4(2x4 - 5xy) could be written as 6x8y4(2x3 - 5y) Either way, once you carry out the multiplication, it becomes 12x11y4 - 30x8y5 I'm guessing the second problem is 25x9 - 10x3 + 5x3 since this website can't reproduce plus signs. That becomes 25x9 - 5x3 which factors to 5x3(5x6 - 1) x^2 and -x^2 cancel each other out, leaving 3549 - 12x which factors to 3(1183 - 4x) -7x^2 - 3x - 21 can be written as -(7x^2 + 3x + 21) but the solution isn't rational.
An expression. It can be factored out slightly too: 2x6 + 5x3 - 7x4 = x3(2x3 - 7x + 5)
20 divided by 4 is 5; 5x3=15 A quarter is 25% or one fourth of a number.
5x3=15 is the inverse
The GCF is 5x
5(x3 - 3x2 - 238)
It is a quadratic expression
y = 5x3 + 6 is a cubic equation, not a linear equation. Linear equations contain only terms of degree 0 (i.e. constants) and terms of degree 1.
Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)
The generalisation is that multiplication is Abelian (or commutative) for numbers.
5" x 3" = 15 square inches.