What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
1
2x (1+3)=(2x1+(2x3)
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
A determinant is defined only for square matrices, so a 2x3 matrix does not have a determinant.Determinants are defined only for square matrices, so a 2x3 matrix does not have a determinant.
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
False
21
no
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
1x6 2x3
1
6 sqft