84 divided by 7 is 12 with remainder 0
7 goes into 84 twelve times exactly (ie there is no remainder).
12 goes into 84 exactly 7 times with nothing left over
88. 12*7=84+4=88
84
21
7 goes into 84 twelve times exactly (ie there is no remainder).
12 goes into 84 exactly 7 times with nothing left over
7 goes into 591 84 times with a remainder of 3
12 goes into 95 7 times
88. 12*7=84+4=88
84
1, 2, 7 and 14 all divide into both 14 and 84, without leaving a remainder.
4.2
7 x 10 = 70 7 x 11 = 77 7 x 12 = 84 89 - 84 = 5 Answer: 12 times with 5 remaining
2619, remainder 4
21
May 12 1984 was on a Saturday. For any date in the 1900s, you can figure out the day of the week in 4 steps: • Month #: (in order, the month #s are: 1 4 4 0 2 5 0 3 6 1 4 6) May => 2 • Date #: 12÷7=1 with a remainder of 5 12th => 5 • Year #: 84÷7=12 with a remainder of 0 '84 => 0 • Leap Year #: 84÷4=21, 21÷7=3 with a remainder of 0 '84 => 0 Finally, divide the sum of all (4) numbers by 7: the remainder is the day o the week 7 ÷ 7 = 1, with a remainder of 0, or the day before the first day of the week Sun = 1st day of the week, so this day (5.12.84) was Saturday.