This is what might be described as a two-step sequence or two sequences spliced together.
t1 = 1
tn = - (tn-1 +1) for n = 2,4,6, ...
and tn = tn-2 + 3 for n = 3,5,7, ...
i0 = 4; in = in-1 - 3
The rule is multiply the previous term by -1 to find the next term.
The pattern will be +2, +3, +4, +4
add 4 to every other number 1(+4)=5, 5(+4)=9 2(+4)=6
3 is the answer
i0 = 4; in = in-1 - 3
Double the previous number
t(n) = 3(n-1) + 1, for n = 1, 2, 3, etc
The rule is multiply the previous term by -1 to find the next term.
The pattern will be +2, +3, +4, +4
add 4 to every other number 1(+4)=5, 5(+4)=9 2(+4)=6
+2, +3, +2
3 is the answer
2 squared 1 = 4 so the divisibility rule is that it is divisible by 1, 2 and 4.
3 4 6 9 13 18...1....2....3....4......5
Subtract 2 from the previous number. 10-2 = 8 8-2 = 6 6-2 = 4 4-2 = 2
5-30-6-42-7-56-8-72