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sum = 138 sample size = 7 138 / 7 ~= 19.714285714285715
mean(18, 23, 39, 10, 22, 17, 16, 15) = (18 + 23 + 39 + 10 + 22 + 17 + 16 + 15) ÷ 8 = 160 ÷ 8 = 20
mean = the sum of the observed values / number of observations = 23+12+15+25+10 / 5 =85/5 =17
The mean is 23.
The question is ambiguous. Does it mean what is 23 (base 10) when converted to base 5 2310 = 435 or what, in base 10, is 23 in base 5 235 = 1310
Sample size: 5 Sum of sample elements: 94 Mean: 94/5 = 18.8
sum = 138 sample size = 7 138 / 7 ~= 19.714285714285715
For not sure might be it is 6.02*10^23
1.51 x 10 ^23 molecules
23
3.24 X 10^23 atom Ba (1mol Ba/6.022 X 10^23 ) = 0.538 moles
3.21 x 10^23
6.022*10^23 molecules of anything is one mole of that thing
.10 mol X (6.02X10 to the 23)/1 mole =6.02x 10 to the 22
The molar mass of copper is approximately 63.5 g. To find how many of these are in our sample we must divide.0.0159/63.5 = 2.5 x 10 ^ -4 = 0.00025 moles. Each mole contains the Avogadro number of atoms, i.e. 6.023 x 10 ^ 23, so in total we have 0.00025x 6.023 x 10 ^ 23 = 1.51 x 10 ^ 20 atoms approximately.
mean(18, 23, 39, 10, 22, 17, 16, 15) = (18 + 23 + 39 + 10 + 22 + 17 + 16 + 15) ÷ 8 = 160 ÷ 8 = 20
mean = the sum of the observed values / number of observations = 23+12+15+25+10 / 5 =85/5 =17