sum = 138 sample size = 7 138 / 7 ~= 19.714285714285715
mean(18, 23, 39, 10, 22, 17, 16, 15) = (18 + 23 + 39 + 10 + 22 + 17 + 16 + 15) ÷ 8 = 160 ÷ 8 = 20
mean = the sum of the observed values / number of observations = 23+12+15+25+10 / 5 =85/5 =17
The mean is 23.
2.3 = 23/10 and reduces to: 2 3/10
Sample size: 5 Sum of sample elements: 94 Mean: 94/5 = 18.8
sum = 138 sample size = 7 138 / 7 ~= 19.714285714285715
For not sure might be it is 6.02*10^23
23
To find the number of moles of zinc, divide the sample's weight by the atomic weight of zinc (65.38 g/mol). This gives approximately 0.534 moles of zinc. To find the number of atoms, multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) to get around 3.21 x 10^23 atoms in the sample.
The molar mass of copper is approximately 63.5 g. To find how many of these are in our sample we must divide.0.0159/63.5 = 2.5 x 10 ^ -4 = 0.00025 moles. Each mole contains the Avogadro number of atoms, i.e. 6.023 x 10 ^ 23, so in total we have 0.00025x 6.023 x 10 ^ 23 = 1.51 x 10 ^ 20 atoms approximately.
To calculate the number of molecules in a sample, you need to know the mass of the sample and the molar mass of the compound. Then you can use Avogadro's number (6.022 x 10^23) to convert from grams to molecules.
6.022*10^23 molecules of anything is one mole of that thing
First, calculate the number of moles in the 40.0 g sample of argon: 40.0 g / 39.948 g/mol = 1.00 mol. Then, use Avogadro's constant (6.022 x 10^23 atoms/mol) to find the number of atoms in 1.00 mol of argon, which is 6.022 x 10^23 atoms.
3.24x10^23 barium atoms represent 0.537 moles, because 1 mole is equivalent to 6.022x10^23 atoms.
mean(18, 23, 39, 10, 22, 17, 16, 15) = (18 + 23 + 39 + 10 + 22 + 17 + 16 + 15) ÷ 8 = 160 ÷ 8 = 20
mean = the sum of the observed values / number of observations = 23+12+15+25+10 / 5 =85/5 =17