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What is the slant height of a triangle if the base is 7 and the height is 23?
Wiki User
∙ 10y ago
Assuming the height to the highest point is in the centre of the base line (i.e. both slant heights are equal) you can use pythagoras theorem. i.e. splitting the triangle into two right angled triangles
23/2 is 11.5. 11.52 + 72 = 181.25. Sq rt 181.25 is 13.463 units
Wiki User
∙ 10y ago
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What is the area of a triangle with base 11 m and height 23 m?
Formula: S=1/2 bh S - area, b - base, h - height S= 1/2 * 11* 23= 126.5
What is the height of a trapezoid with a base one of 23 base 2 of 15 and sides of 8.5 and 10?
I don't know if this is the most efficient way to get to the answer (short of looking at the back of the book), but here goes: Remove a parallelogram with top and bottom of 15 units from the trapezium. This will leave a triangle with base 23-15=8, and sides of 8.5 and 10. The area of this triangle, in terms of its sides, a, b and c, is sqrt[s*(s-a)*(s-b)*(s-c)] where s = (a+b+c)/2 That is, the area of the triangle is 32.77 square units. Now, the area of the triangle is also base*height/2 So 8*Height/2 = 32.77 That is, Height = 32.77/4 = 8.1925 units
The volume of a rectangular pyramid with base 23 m2 and height 5 m?
volume_of_pyramid = 1/3 x base_area x height volume = 1/3 x 23 m2 x 5 m ~= 38.3 m3
If the hypotnuse of a right triangle is 31 an the leg length is 23 what is the base length?
sqrt(312 - 232) = sqrt(432) = 20.785 units
If a right triangle's hypotnuse 31 an the leg length 23 what does that leave the base?
an exact answer would be twelve times the square root of three
The height of a triangle is 3cm. If the area is 30cm^2 what is the length of the base of the triangle Show your work?
23
What is the volume of a triangle prism when the area of the base is 54m squared and the height is 23 m?
Volume of prism = Base area x height = 54 square metres x 23 metres = 1242 cubic metres.
What is the area of a triangle with base 11 m and height 23 m?
Formula: S=1/2 bh S - area, b - base, h - height S= 1/2 * 11* 23= 126.5
What is the height of a trapezoid with a base one of 23 base 2 of 15 and sides of 8.5 and 10?
I don't know if this is the most efficient way to get to the answer (short of looking at the back of the book), but here goes: Remove a parallelogram with top and bottom of 15 units from the trapezium. This will leave a triangle with base 23-15=8, and sides of 8.5 and 10. The area of this triangle, in terms of its sides, a, b and c, is sqrt[s*(s-a)*(s-b)*(s-c)] where s = (a+b+c)/2 That is, the area of the triangle is 32.77 square units. Now, the area of the triangle is also base*height/2 So 8*Height/2 = 32.77 That is, Height = 32.77/4 = 8.1925 units
A parolellogram has an area of 92 if the height is 4 what is the base?
23.
What is the area of a triangle with a height of13cm and the base of 46cm?
A= 1/2 B x H A=1/2(46) x 13 A=23 x 13 =299 Area= 299cm
The base of a triangle exceeds the height by 4 feet if the area is 218.5 square feet find the length of a base and the height of the triangle?
Let the base be x+4 and the length be x: 1/2*(x+4)*x = 218.5 square feet Multiply both sides by 2 to eliminate the fraction: (x+4)*x = 437 Multiply out the brackets: x2+4x = 437 x2+4x-437 = 0 Solving the above by using the quadratic equation formula will result in: x = -23 or x = 19 so x must be the latter because dimensions can't be negative. Therefore: base = 23 feet and height = 19 feet Proof: 1/2*23*19 = 218.5 square feet
How do you increase my height in 23 age?
how i increase my height at 23 years
The volume of a rectangular pyramid with base 23 m2 and height 5 m?
volume_of_pyramid = 1/3 x base_area x height volume = 1/3 x 23 m2 x 5 m ~= 38.3 m3
If the hypotnuse of a right triangle is 31 an the leg length is 23 what is the base length?
sqrt(312 - 232) = sqrt(432) = 20.785 units
If a right triangle's hypotnuse 31 an the leg length 23 what does that leave the base?
an exact answer would be twelve times the square root of three
Can you find the volume of a cylinder whose base has a diameter of 14 feet and whose height is 23 feet?
Yes indeed ! I certainly can.
