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What is the area of a triangle with base 11 m and height 23 m?
Formula: S=1/2 bh S - area, b - base, h - height S= 1/2 * 11* 23= 126.5
What is the height of a trapezoid with a base one of 23 base 2 of 15 and sides of 8.5 and 10?
I don't know if this is the most efficient way to get to the answer (short of looking at the back of the book), but here goes: Remove a parallelogram with top and bottom of 15 units from the trapezium. This will leave a triangle with base 23-15=8, and sides of 8.5 and 10. The area of this triangle, in terms of its sides, a, b and c, is sqrt[s*(s-a)*(s-b)*(s-c)] where s = (a+b+c)/2 That is, the area of the triangle is 32.77 square units. Now, the area of the triangle is also base*height/2 So 8*Height/2 = 32.77 That is, Height = 32.77/4 = 8.1925 units
If the hypotnuse of a right triangle is 31 an the leg length is 23 what is the base length?
sqrt(312 - 232) = sqrt(432) = 20.785 units
If a right triangle's hypotnuse 31 an the leg length 23 what does that leave the base?
an exact answer would be twelve times the square root of three
The volume of a rectangular pyramid with base 23 m2 and height 5 m?
volume_of_pyramid = 1/3 x base_area x height volume = 1/3 x 23 m2 x 5 m ~= 38.3 m3
The height of a triangle is 3cm. If the area is 30cm^2 what is the length of the base of the triangle Show your work?
23
What is the area of a triangle with base 11 m and height 23 m?
Formula: S=1/2 bh S - area, b - base, h - height S= 1/2 * 11* 23= 126.5
What is the volume of a triangle prism when the area of the base is 54m squared and the height is 23 m?
Volume of prism = Base area x height = 54 square metres x 23 metres = 1242 cubic metres.
What is the height of a trapezoid with a base one of 23 base 2 of 15 and sides of 8.5 and 10?
I don't know if this is the most efficient way to get to the answer (short of looking at the back of the book), but here goes: Remove a parallelogram with top and bottom of 15 units from the trapezium. This will leave a triangle with base 23-15=8, and sides of 8.5 and 10. The area of this triangle, in terms of its sides, a, b and c, is sqrt[s*(s-a)*(s-b)*(s-c)] where s = (a+b+c)/2 That is, the area of the triangle is 32.77 square units. Now, the area of the triangle is also base*height/2 So 8*Height/2 = 32.77 That is, Height = 32.77/4 = 8.1925 units
A parolellogram has an area of 92 if the height is 4 what is the base?
23.
What is the area of a triangle with a height of13cm and the base of 46cm?
A= 1/2 B x H A=1/2(46) x 13 A=23 x 13 =299 Area= 299cm
The base of a triangle exceeds the height by 4 feet if the area is 218.5 square feet find the length of a base and the height of the triangle?
Let the base be x+4 and the length be x: 1/2*(x+4)*x = 218.5 square feet Multiply both sides by 2 to eliminate the fraction: (x+4)*x = 437 Multiply out the brackets: x2+4x = 437 x2+4x-437 = 0 Solving the above by using the quadratic equation formula will result in: x = -23 or x = 19 so x must be the latter because dimensions can't be negative. Therefore: base = 23 feet and height = 19 feet Proof: 1/2*23*19 = 218.5 square feet
How do you increase my height in 23 age?
how i increase my height at 23 years
If the hypotnuse of a right triangle is 31 an the leg length is 23 what is the base length?
sqrt(312 - 232) = sqrt(432) = 20.785 units
If a right triangle's hypotnuse 31 an the leg length 23 what does that leave the base?
an exact answer would be twelve times the square root of three
The volume of a rectangular pyramid with base 23 m2 and height 5 m?
volume_of_pyramid = 1/3 x base_area x height volume = 1/3 x 23 m2 x 5 m ~= 38.3 m3
Can you find the volume of a cylinder whose base has a diameter of 14 feet and whose height is 23 feet?
Yes indeed ! I certainly can.
