The slope intercept form for a equation is y = mx + b
With this in mind, the equation 6x + 11y = -77 must be in terms of x
So:
11y = -6x - 77
y = (-6x)/7 - (77)/7
y = (-6/7)x - 11
m = -6/7
b = -11
Slope-Intercept Form: y = -2x +1
Solving the equation for "y" gives you the slope-intercept form.
Yes, that is the slope intercept form of the equation for a straight line.
y= -4x + 10 Slope intercept form is y=mx+b
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.
It is: y = -0.4x+1 when in slope intercept form.
y = -1.2x-3 in slope intercept form
Slope-Intercept Form: y = -2x +1
y = 6x+8 is already in slope intercept form
It is: y = -7x+1 in slope intercept form
Solving the equation for "y" gives you the slope-intercept form.
Yes, that is the slope intercept form of the equation for a straight line.
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y= -4x + 10 Slope intercept form is y=mx+b
Slope-intercept form
That is slope-intercept form of a line.
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.