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You can graph a linear equation slope intercept by solving the equation and plugging in the numbers : y=mx+b
5
[ y = 12x ] is an equation, not a 'problem'. The graph of that equation is a straight line with a slope of 12 .
35
y=-5x+8 the slope is -5.
The equation has no slope. The graph of the equation is a straight line with a slope of -1 .
You can graph a linear equation slope intercept by solving the equation and plugging in the numbers : y=mx+b
23
5
[ y = 12x ] is an equation, not a 'problem'. The graph of that equation is a straight line with a slope of 12 .
35
y=-5x+8 the slope is -5.
If that should be y = 2 the slope is 0 and the y intercept is 2.
1
If you have anything that you're planning to graph, it's got to be an equation that has 'x' and 'y' in it. If you have an equation that has 'x' and 'y' in it and you're planning to graph the equation, then you've had enough elementary algebra to know how to solve the equation for 'y'. Do that first and bada bing, it'll be in slope/intercept form.
The graph of an equation can have a slope and an intercept. Sadly, "x-y-1" is not an equation, so it doesn't have any.
The equation for the slope of a linear equation is Y=Mx+b, where m is the slope of the line, (Rise over run) and where B is the Y-intercept. (Where it crosses the Y axis)