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-5=-3x+19 divide both sides by 3
y=-3/5x-19/5 So the slope will be -3/5.
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What is the slope of the line that contains the points -32 23 and -32 -19?
It has no slope.
What is the slope if the line that passes through the points -19 and 46?
To work this out get some graph paper and draw the line.
If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?
negative 1/2
What is the slope of -11-17 -14-19?
Points: (-11, -17) and (-14, -19) Slope: 2/3
What us the equation of the following line (19)(00)?
Points: (1, 9) and (0, 0) Slope: 9 Equation: y = 9x
What is the slope of the line that contains the points -32 23 and -32 -19?
It has no slope.
What is the gradient of y equals 9x-10?
19
What is the slope of the line that contains the points (-19) and (521)?
(-1,9) (5,21)
What is the slope of a line that contains the point -19 and 521?
If you mean points of (-1, 9) and (5, 21) then the slope works out as 2
What is the slope if the line that passes through the points -19 and 46?
To work this out get some graph paper and draw the line.
If line AB contains the points 4 19 and -3 5 what is the slope of a line perpendicular to AB?
-1/2 or -0.50
If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?
negative 1/2
Find the slope of line through pair of points 19-16 -7-15?
-15-16/-7-19=-1/26
-x plus 19y equals 38 as slope intercept form?
Slope intercept form is of the form y = mx + c -x + 19y = 38 → 19y = x + 38 → y = 1/19 x + 2 (or y = x/19 + 2)
What is the slope of a line that contains the points (-19) and (521)?
If you mean points of (-1, 9) and (5, 21) then the slope of the line works out as 2
Find th slope if it exists of the line containing the pair of points -5-13 and -17-19?
First we note that the slope does exist between the two points because the two points do not have the same x co-ordinate. Next, we apply the slope formula. slope=(y2-y1)/(x2-x1) Note that it does not matter which point you call as 1 or 2, you will still get the same result. For this example we will call point (-5,-13) as point 1 and (-17,-19) as point 2. Therefore: slope=(-19-(-13)) / (-17-(-5)) = (-6) / (-12) = 1/2 Therefore, the slope of the line containing the points (-5,-13) and (-17,-19) is 1/2.
What is the equation in slope intercept form of the line joining the points -2.5 -0.5 and 4.5 -1?
Points: (-2.5, -0.5) and (4.5, -1) Slope: -1/14 Equation: y = -1/14x-19/28 in slope intercept form
