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What is the slope of the line that contains the points -32 23 and -32 -19?
It has no slope.
What is the slope if the line that passes through the points -19 and 46?
To work this out get some graph paper and draw the line.
If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?
negative 1/2
What is the slope of (-20 -18) and (19 5)?
To find the slope between the points (-20, -18) and (19, 5), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the values, we get ( m = \frac{5 - (-18)}{19 - (-20)} = \frac{5 + 18}{19 + 20} = \frac{23}{39} ). Therefore, the slope of the line connecting these two points is ( \frac{23}{39} ).
What is the slope of 1-19 -2-7?
To find the slope of the line represented by the points (1, -19) and (-2, -7), use the slope formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (1, -19) ) and ( (x_2, y_2) = (-2, -7) ). Substituting the values, we get ( m = \frac{-7 - (-19)}{-2 - 1} = \frac{12}{-3} = -4 ). Thus, the slope is -4.
What is the slope of the line that contains the points -32 23 and -32 -19?
It has no slope.
What is the gradient of y equals 9x-10?
19
What is the slope of the line that contains the points (-19) and (521)?
(-1,9) (5,21)
What is the slope of a line that contains the point -19 and 521?
If you mean points of (-1, 9) and (5, 21) then the slope works out as 2
What is the slope if the line that passes through the points -19 and 46?
To work this out get some graph paper and draw the line.
If line AB contains the points 4 19 and -3 5 what is the slope of a line perpendicular to AB?
-1/2 or -0.50
If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?
negative 1/2
Find the slope of line through pair of points 19-16 -7-15?
-15-16/-7-19=-1/26
What is the slope of (-20 -18) and (19 5)?
To find the slope between the points (-20, -18) and (19, 5), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the values, we get ( m = \frac{5 - (-18)}{19 - (-20)} = \frac{5 + 18}{19 + 20} = \frac{23}{39} ). Therefore, the slope of the line connecting these two points is ( \frac{23}{39} ).
What is the slope of 1-19 -2-7?
To find the slope of the line represented by the points (1, -19) and (-2, -7), use the slope formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (1, -19) ) and ( (x_2, y_2) = (-2, -7) ). Substituting the values, we get ( m = \frac{-7 - (-19)}{-2 - 1} = \frac{12}{-3} = -4 ). Thus, the slope is -4.
-x plus 19y equals 38 as slope intercept form?
Slope intercept form is of the form y = mx + c -x + 19y = 38 → 19y = x + 38 → y = 1/19 x + 2 (or y = x/19 + 2)
What is the slope of a line that contains the points (-19) and (521)?
If you mean points of (-1, 9) and (5, 21) then the slope of the line works out as 2
