Q: What is the smallest number that can be divided by 234 and 5 to give remainder of 1 in each case but when divided by 11 gives no remainder?

Write your answer...

Submit

Related questions

12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.

0.6667

221 is the smallest number which when divided by 24 36 and 54 gives a remainder of 5 each time

42

0.4444

124

169 is the smallest such number.

8.

3, when divided by 2.

23, 58, 93, 128, 163, 198, ...

3

23 is an odd number between 10 and 30 that gives a remainder of 2 when divided by 7.

-2

40

447

3 divided by 2 goes once, remainder one.

172

69.

89

77/6 = 12 remainder 5

12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.

No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)

200

Any prime number greater than 11.

3 divided by 2 gives 1r1

Study guides