Q: What is the smallest whole number that gives a remainder of 4 when it is divided by 8?

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3 divided by 2 goes once, remainder one.

To determine if 65483 is divisible by a certain number, you would typically divide 65483 by that number and check if the remainder is zero. 65483 divided by 2 has a remainder, so it is not divisible by 2. 65483 divided by 3 also has a remainder, so it is not divisible by 3. However, 65483 divided by 7 gives a remainder of 0, so it is divisible by 7.

403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.

165

12 ÷ 6 = 2

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221 is the smallest number which when divided by 24 36 and 54 gives a remainder of 5 each time

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The smallest number is 9361. 9361 = 40*234 + 1 9361 = 1872*5 + 1 9361 = 11*851

169 is the smallest such number.

3, when divided by 2.

8

8.

12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.

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