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Q: What is the smallest number which when divided by 24 36 and 54 gives a remainder of 5 each time?

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The smallest number is 9361. 9361 = 40*234 + 1 9361 = 1872*5 + 1 9361 = 11*851

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12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.

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