234568
5
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
41
6
121.
forty-one
36
71
It is LCM(5, 8) + 1 = 41.
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
HCF(5, 8) + 1 = 40 + 1 = 41