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It is LCM(5, 8) + 1 = 41.

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41

Q: What is the lowest positive integer greater that 1which then divided by 5 or 8 leaves a remainder of 1?

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The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3

forty-one

0, 1, 2, or 3.

41

6172839

Related questions

234568

5

41

41

The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3

forty-one

12

0, 1, 2, or 3.

41

6172839

HCF(5, 8) + 1 = 40 + 1 = 41

85