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Wiki User
It is LCM(5, 8) + 1 = 41.
41
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5
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The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
forty-one
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0, 1, 2, or 3.
HCF(5, 8) + 1 = 40 + 1 = 41
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