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All you need is the moles and the mass of NaHCO3 and you have the moles

0.025 moles NaHCO3 (84.008 grams/1 mole NaHCO3)

= 2.1 grams of sodium bicarbonate

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Q: What is the solute mass of NaHCO3 if mol solute is 0.025 volume solution is 0.25 liters and molarity 0.100M?
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