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What is the solution is the of this equation root 7- 1 divide by root 7 plus 1 - root 7 plus 1 divide by root 7 - 1?
Wiki User
∙ 12y ago
It will depend on where you put your parentheses.
Root 7 -( 1/root 7) is different from (root 7-1)/root 7.
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True, but a more helpful answer:
[sqrt(7) - 1]/[sqrt(7) + 1] - [sqrt(7) + 1]/[sqrt(7) - 1]
Multiplying the numerator and denominator of the first fraction by [sqrt(7) - 1]
and the second fraction by [sqrt(7) + 1]
= [sqrt(7) - 1]2/[7 - 1] - [sqrt(7) + 1]2/[7 - 1]
=[7 - 2*sqrt(7) + 1]/6 - [7 + 2*sqrt(7) + 1]/6
= 16/6 = 8/3
Wiki User
∙ 12y ago
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root
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-2
What is the term used for a quantity which when substituted for the unknown quantity in an equation satisfies the equation?
It is the solution to the equation or a root of the equation.
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What is the root of 2m plus 7 equals 8 plus m?
We're not sure what the question means by "root". It may be what's usuallyreferred to as the "solution" of the equation ... the number that 'm' must be inorder to make the equation a true statement. Here's how to find the 'solution':2m + 7 = 8 + mSubtract 7 from each side:2m = 1 + mSubtract 'm' from each side:m = 1
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Such a value is called a "solution" or "root" of an equation.
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