There are two equations for which we must determine both variables, x and y.
3y = 5x
y = x + 2
We are going to use the substitution method to isolate one of the variables in one of the equations. The second equation defines "y" for us in terms of "x", so we will simply substitute that value into the first equation
3y = 5x
3(x + 2) = 5x
3x + 6 = 5x
6 = 2x
x = 3
Now that we have a value for "x", we will substitute that back into the second equation to get a numerical value for "y".
y = x + 2
y = 3 + 2
y = 5
Then, do not forget to check your work by putting both values into both equations to make sure you have the correct answer.
3y = 5x
3(5) = 5(3)
15 = 15
Check!
y = x + 2
5 = 3 + 2
5 = 5
Check!
There are two solutions and they are: x = -1 and y = 3
-10
x = 1 and y = 2
2x - y = 2 2x - y = -2 This system is inconsistent -- that is, there is no solution. To help see why, let Z = 2x - y and notice Z can't be 2 and -2 at the same time.
It works out that x = 0 and y = 3
x = y = 3
{-1,-2}
x = 3, y = 3
There are two solutions and they are: x = -1 and y = 3
No solution
-10
7
If "equations-" is intended to be "equations", the answer is y = -2. If the first equation is meant to start with -3x, the answer is y = 0.2
When the dissolving rate equals the rate at which molecules comes out of solution the solution is in 'equilibrium'.
-1
The list of choices you've provided doesn't include any solution.
It is (-1, 3).