x=6y-4
x=-2y+28
Substitute (6y-4) for x in the second equation and solve for y:
6y-4=-2y+28
8y=32
y=4
Then solve for x:
x=6(4)-4=20
(20,4)
X = 135 and y = 15 Solved by addition and substitution
If: y = x+6 and y = 2x Then: x+6 = 2x And: 6 = 2x-x => 6 = x So: x = 6 and y = 12
Using the quadratic equation formula: x = -5-/+ the square root of 7
It is (-1, 3).
The solution is: x = 1 and y = -1
x = -2 and y = 1
-10
-2
If you mean: x+7y = 7 and 2x+y = 8 Then by substitution: x = 49/13 and y = 6/13
If you mean: x+7y = 39 and 3x-2y = 2 Then by substitution: x = 4 and y = 5
A solvent plus a solute equals a solution.
Yes its on the line.
You'd need another equation to sub in
2x-3y=13
Solve this system of equation using substitution 2x plus 6y equals 24 and 3x-2x equals 24 ?Improved Answer:2x+6y = 243x-2x = 24 => x =24Substitute the value of x into the top equation to find the value of y:48+6y = 246y = 24-486y = -24y = -4So: x = 24 and y = -4
Substitution property.
42