19
x+(x+2)+(x+4)=51 (In bold is the number you're looking for)
3x+6=51 (Simplify it to find x)
3x=45
x=15
15+4=19 (Now add the 4 back to it to match the bold "x+4" from earlier)
The sum of any three consecutive even numbers must be divisible by 3. 32 is not, so there is no solution.
The largest is 73.
6 + 8 + 10 = 24Therefore the largest of the three numbers will be 10.
12, 13 and 14
202 + 222 = 400 + 484 = 884
The sum of any three consecutive even numbers must be divisible by 3. 32 is not, so there is no solution.
The largest is 73.
101 + 102 + 103 (That's the only one.)
6 + 8 + 10 = 24Therefore the largest of the three numbers will be 10.
12, 13 and 14
202 + 222 = 400 + 484 = 884
14, 15, 16
21.
94+95+96 96
Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
let largest number be x, other numbers are x-1,x-2 (since they are consecutive) now, it says x+(x-1) + (x-2)= 18 = 3x -3=18 = 3x= 18+3 = 3x= 21 = x= 21/3 = x= 7 therefore largest number is 7.