0
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2.
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
What comes next in this sequence 10 30 15 16 48 24 25?
75x3, /2, +1, x3...10 x3=30 /2=15 +1=16 x3=48 /2=24 +1=25 x3=75
What is the solution set for -x3-2x2-x-2?
There can be no solution set because there is no equation or inequality, only an expression.
X cubed plus x equals -2?
x3 + x = -2 => x3 + x + 2 = 0 => x3 + x2 - x2 - x + 2x - 2 = 0 => x2(x+1) - x(x+1) + 2(x+1) = 0 => (x+1)*(x2-x+2) = 0 Setting the first bracket equal to zero gives the only real solution, which is x = -1 The second bracket gives the complex roots, x = ½*[1 +or- i*sqrt(7)]
What is x cubed times 1 half times the squared root of x cubed?
x3*(1/2)*sqrt(x3) = 1/2*x4.5 or 1/2*sqrt(x9)
How do you factorise x cubed take one?
If it's (x3 -1) that you want to factorize, then find the solutions to (x3 -1) = 0.So if P(x) is a polynomial of x, and x=a is a solution for P(x) = 0, then (x - a) is a factor of P(x).So x = 1 solves (x3 -1) = 0, so (x - 1) is a factor. Use long division (x3 -1)/(x-1) = x2 + x + 1. Use the quadratic formula to find the roots of this: -1/2 ± i*sqrt(3)/2, which is complex. So the factorization is:(x3 -1) = (x - 1)( x2 + x + 1)Multiply the polynomials together to check that your answer is correct.
What is the solution to x cube -4 equals 2?
X3 - 4 = 2 X3 = 6 X = 61/3 X = about 1.817
What comes next in this sequence 10 30 15 16 48 24 25?
75x3, /2, +1, x3...10 x3=30 /2=15 +1=16 x3=48 /2=24 +1=25 x3=75
What is the solution set for -x3-2x2-x-2?
There can be no solution set because there is no equation or inequality, only an expression.
X cubed plus x equals -2?
x3 + x = -2 => x3 + x + 2 = 0 => x3 + x2 - x2 - x + 2x - 2 = 0 => x2(x+1) - x(x+1) + 2(x+1) = 0 => (x+1)*(x2-x+2) = 0 Setting the first bracket equal to zero gives the only real solution, which is x = -1 The second bracket gives the complex roots, x = ½*[1 +or- i*sqrt(7)]
What is x cubed times 1 half times the squared root of x cubed?
x3*(1/2)*sqrt(x3) = 1/2*x4.5 or 1/2*sqrt(x9)
Factor the polynomial x3-2x2 plus x-2?
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
What is 1 plus 2 X3?
7
How do you factorise x cubed take one?
If it's (x3 -1) that you want to factorize, then find the solutions to (x3 -1) = 0.So if P(x) is a polynomial of x, and x=a is a solution for P(x) = 0, then (x - a) is a factor of P(x).So x = 1 solves (x3 -1) = 0, so (x - 1) is a factor. Use long division (x3 -1)/(x-1) = x2 + x + 1. Use the quadratic formula to find the roots of this: -1/2 ± i*sqrt(3)/2, which is complex. So the factorization is:(x3 -1) = (x - 1)( x2 + x + 1)Multiply the polynomials together to check that your answer is correct.
Can you multiply 3 consecutive numbers and get 2015?
This is the same as asking is there an integer solution to x(x+1)(x+2)=2015.x3 -3x2 +2x=2015So we must solve x3 -3x2 +2x-2015=0 for integer solutions.The solution is x=13.657 which is not an integer. That is the only real solution.So the answer is no.
How do you factor x3 plus 1?
x3 + 1 = x3 + x2 - x2 - x + x + 1 = x2(x + 1) - x(x + 1) +1(x + 1) = (x + 1)(x2 - x + 1)
What number is next in the following sequence 10 30 15 16 48 24?
10 30 15 16 48 24 25 x3 1/2 +1 x3 1/2 +1
What is the inverse of x3 plus 1?
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
