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5a - 1 = a - 7 4a = -6 a = -1.5
5a + 2 = 7 subtract 2 from both sides: 5a = 5 divide both sides by 5: a = 1
6a + 5a = -11 11a = -11 a = -11/11 = -1
So we have 5a + 11 + 3a - 7 = -4 Start by combining common terms such as the 5a and 3a to give you 8a and 11 and -7 to give you 4. So now your equation is 8a + 4 = -4. Subtract 4 from both sides gives you 8a = -8. Divide -8 by 8 to give you a = -1, your solution.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
If: 2a+13 = 5a+1 Then: a = 4
5a - 1 = a - 7 4a = -6 a = -1.5
An equation that has no solution is called an equation that has no solution.
5a + 2 = 7 subtract 2 from both sides: 5a = 5 divide both sides by 5: a = 1
6a + 5a = -11 11a = -11 a = -11/11 = -1
So we have 5a + 11 + 3a - 7 = -4 Start by combining common terms such as the 5a and 3a to give you 8a and 11 and -7 to give you 4. So now your equation is 8a + 4 = -4. Subtract 4 from both sides gives you 8a = -8. Divide -8 by 8 to give you a = -1, your solution.
It is an expression because it does not contain an equality sign.
i dont understand what you mean by symbolic but ill just do an example 2a + 3 = 4 - 5a first collect like terms 2a +3 -3 = 4 -3 -5a 2a = 4-3 - 5a 2a + 5a = 1 - 5a + 5a 2a + 5a = 1 7a = 1 divide both sides by the coefficient of the unknwown(i.e. the number in front of the letter) 7a/7 = 1/7 a = 1/7
Because of limitations with the question software, some symbols cannot be rendered, so we don't know what operation there is between the 5a and the 4a-1. Assuming a plus sign produces an inconsistent equation. But if we assume a / (slash) for division, we get a quadratic equation that produces some reasonable roots, so here's what I think the question is: Can you solve the following equation for a: 5a/(4a-1) = 9a-4 ? Yes you can! Multiply both sides of the equation by 4a-1. This gives you: 5a = (9a-4)(4a-1) Expand the right side, which gives you 5a = 36a2 -9a -16a + 4 Subtract 5a from both sides and group similar terms: 0 = 36a2 -30a + 4 Now, use the quadratic formula to solve for a(left to the student): a1 = 2/3; a2 = 1/6
1+1=2
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
Yes and sometimes it can have more than one solution.