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What is the solution to the system of equations y equals x squared plus 9 and y equals 6x plus 2?
Wiki User
∙ 6y ago
If:
y = x² + 9
and
y = 6x + 2
then
x² + 9 = 6x + 2
→ x² - 6x + 7 = 0
→ x = (6 ± √(6² - 4×1))/2 = (6 ± √8)/2 = (6 ± 2√2)/2 = 3 ± √2
Substituting in the second to find the corresponding y:
→ x = 3 - √2 → y = 6(3 - √2) + 2 = 20 - 6√2
or x = 3 + √2 → y = 6(3 + √2) + 2 = 20 + 6√2
The solution is the two points:
(3 - √2, 20 - 6√2) and (3 + √2, 20 + 6√2)
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoThe solutions are: [3 - sqrt(2), 20 - 6*sqrt(2)] and [3 + sqrt(2), 20 + 6*sqrt(2)]
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