The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
The solutions are: x = 4, y = 2 and x = -4, y = -2
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
They are: (3, 1) and (-11/5, -8/5)
Because 6 squared equals 36 and 36 terminates, or ends, which makes it rational.
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
Equations: 3x-5y = 16 and xy = 7 Solutions: (7, 1) and (-5/3, -21/5)
It works out that the solutions are: x = 3 and y = 2
0 = 0 is an identity and not an equation. Equations have solutions, identities do not.
The quadratic equation will have two solutions.
They are called the solutions or roots of the equations.
If the equation is x2 = k0 Then there are two solutions: + or - 1, since any number to 0 is 1 and 1 or -1 squared = 1.