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If you mean (1) y + 3x = 22 and (2) y + 2x = 16, then

(1) y = 22 - 3x (sub this into (2))

(2) (22 - 3x) + 2x = 16

-x = -6

x = 6

y = 22 - 3x = 22 -3(6) = 4

solution: (6,4)

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Q: What is the solution to y3x 22 y2x 16 by using systems by substitution?
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