Just divide the distance by the time. The answer will be in m/sec.
To calculate the speed of the car, you would use the formula speed = distance/time. In this case, the distance is 100 meters and the time is 50 seconds. Plugging these values into the formula, you get speed = 100 meters / 50 seconds = 2 meters per second. Therefore, the speed of the car is 2 meters per second.
The speed of an object in free fall increases by 9.8 m/s every second. Therefore, after 2 seconds of free fall, the speed of the ball will be 9.8 m/s * 2 seconds = 19.6 m/s.
50 metres in 5 seconds = 50/5 = 10 metres per second.
The object's speed after falling for 2 seconds can be calculated using the formula: speed = acceleration due to gravity (9.81 m/s^2) x time (2 s). Therefore, the speed of the object after falling for 2 seconds would be 19.62 m/s.
Speed (m/s) = Distance (m) / Time (s)Speed = 400 / 50Average Speed = 8 metres per second
2 m/s
Initial speed = 10 m/s.Final speed = 0 m/sAverage speed = 1/2 (10 + 0) = 5 m/s.At the average speed of 5 m/s, it will take (250/5) = 50 seconds to stop exactly at the end of the ramp.Deceleration is (change in speed) divided by (time) = -10/50 = -0.2 m/s2
speed = distance/time --> time = distance/speed = (30 m)/(50 m/s) = 0.6 seconds
16.7 meters/sec
Any force in the direction she's moving will cause her speed to increase.The more force you use, the faster her speed will increase.If you want to increase her speed by 2 m per sec in one second, then you want heracceleration to be (change in speed)/(time for the change) = 2/1 = 2 m/sec2 .F = M A = (50) (2) = 100 newtonsIf you want to increase her speed by 2 m per sec in 0.1 second, then you want heracceleration to be (change in speed)/(time for the change) = 2/0.1 = 20 m/sec2 .F = M A = (50) (20) = 1,000 newtons.If you want to increase her speed by 2 m per sec in 1 minute, then you want heracceleration to be (change in speed)/(time for the change) = 2/60 .F = M A = (50) (2/60) = 1.667 newtons.
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is
If he started out from "rest" (zero speed), then his average acceleration for the 5 seconds is50/5 = 10 meters per second2