(n+4)2 = 36
This is your equation. To solve for it square root of both sides then minus the 4 from both sides and you find your "n"
n+4= 6
n=2
Your variable equals 2
x^2+4^2 =36
the sum of 8 and 4 times a number is 36
The square roots of 36 are +6 and -6 .
13th square number = 169 2nd square number = 4 169 + 4 = 173
4*4=16 sum of 1+6 is 7, difference is 5 so 16 is answer
The most obvious answer here is to simply take it's square root, and see if the answer is an integer. If it is, then your number is a perfect square. If you don't know it's square root offhand and don't have a calculator handy, you could do it by adding up a series of odd numbers, and seeing if they reach a sum that is equal to the original number. If they do, then you have a perfect square. Otherwise, you don't. For example, is 36 a perfect square? Let's find out: 0 + 1 = 1 1 + 3 = 4 4 + 5 = 9 9 + 7 = 16 16 + 9 = 25 25 + 11 = 36 Since we hit 36 with our addition, we know that 36 is indeed a perfect square.
The number is 4 (4+3) * (4+3) = 49 (4+2) * (4+2) = 36 49 - 36 = 13
the sum of 8 and 4 times a number is 36
Part1: Finding probability of getting sum as a perfect square. Maximum sum of both the dice is (6+6) equal to 12. Up to 12, the perfect squares are: 1, 4 and 9. Getting a sum of 1 from two dice is not possible. So, we are left with 4 and 9. To get 4, the combination can be: (2,2) or (1,3) or (3,1). This means, to get the sum as 4, the probability is [3/36]. To get 9, the combination can be: (3,6) or (6,3) or (5,4) or (4,5). This means, to get the sum as 9, the probability is [4/36]. Therefore,the total probability of getting the sum as a perfect square is: [(3/36)+(4/36)]=[7/36]. Part2: Finding the probability of getting sum as an even number. The possible even numbers can be 2, 4, 6, 8, 10 and 12. But, as 4 is already considered in part1, it should be ignored in this case. The probability of getting sum as 2 is: [1/36] The probability of getting sum as 6 is: [5/36] The probability of getting sum as 8 is: [5/36] The probability of getting sum as 10 is: [3/36] By adding all the above, the probability of getting sum as an even number (ignoring 4) is: [(1/36)+(5/36)+(5/36)+(3/36)]=[14/36]. From part 1 and part 2, we get the total probability as [(7/36)+(14/36)]=[7/12]=0.583333.
n is a square of a rational number. For example, 4 or 81, or 2.25 or 36/25.n is a square of a rational number. For example, 4 or 81, or 2.25 or 36/25.n is a square of a rational number. For example, 4 or 81, or 2.25 or 36/25.n is a square of a rational number. For example, 4 or 81, or 2.25 or 36/25.
The square roots of 36 are +6 and -6 .
it is 36!!! because,,, # 3+6=9 # 6x6=36 # factors are: 1 2 3 4 6 9 12 18 36= 9 factors # 36= an even number it all works so the answer is 36!
12+22+32+42+52+62 = 1+4+9+16+25+36= 91
13th square number = 169 2nd square number = 4 169 + 4 = 173
16 or 36 16/4 = 4 √16 = 4 16 < 50 36/4 = 9 √36 = 6 36 < 50
Yes. A square number is a number that it is the product of some integer with itself. For example, 2 x 2 = 4, thus 4 is a square number. Other square numbers include 9 (3 x 3), 16 (4 x 4), and 25 (5 x 5). 36 is a square number because 6 x 6 = 36.
The proper factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18. Their sum is: 1 + 2 + 3 + 4 + 6 + 9 + 12 + 18 = 55. As their sum (55) is greater than 36, the number 36 is an abundant number.
How about 36 because 6*6 = 36 and 4*9 = 36