4*4=16 sum of 1+6 is 7, difference is 5 so 16 is answer
There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.
49
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
A number is divisible by 33 ifthe sum of the digits is 0, 3, 6 or 9;andthe difference between (the sum of the digits in the odd places) and (the sum of the digits in the even places) is 0, 11, 22, 33, ... . This process may require repeating if the original number is very large,
1 + 1 = 2 The sum of the digits is therefore 2.
81
81...........
let the no. be 9 square of 9=9*9=81 sum of the digits of square = 8+1=9 so if the no.=sum of the digits the it is a neon number
28
There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.
28
To find the sum of the square roots of the digits in the number 121, we first identify its digits: 1, 2, and 1. The square roots of these digits are √1 = 1, √2 ≈ 1.41, and √1 = 1. Adding these together gives us 1 + 1.41 + 1 = 3.41. Thus, the sum of the square roots of the digits in 121 is approximately 3.41.
81
you are the number 48
81
49
The number is 81.