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Q: What is the square root of 128?

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The number is the square root of 128 times the square root of 128 = 128

The square root of 128 is an irrational number.

It's the other way around. The square root of 128 lies between 11 and 12.

the square root of 128 or 8 times the square root of 2.

square root of 128

Out of these numbers, 225 is a square number since the square root of 225 is 15.

It is irrational.

The square root of 128, approxiametaly 11.313

8 x y1.5 sqrt(2)

128 = 8*8*2 so sqrt(128) = sqrt(8*8*2) = sqrt(8*8)*sqrt(2) = sqrt(82)*sqrt(2) = 8*sqrt(2) since the sqrt of a square is the number itself.

8√2i

The seventh root of 128 is two.

8 times [ square root of 2 ] .

128 = 64 x 2 so sqrt = 8 x root 2 or "8 root 2" 128 = 2^7 = 2^6 × 2 → √128 = √(2^6 × 2) = √(2^6) √2 = 2^3 √2 = 8 √2

In a triangle ABC, when hypotenuse is 128 unit which is right angled at A. By phythagoras theorem H square = P square + B square root of hypotenuse = ROOT of 8square + root of 8square it means other two sides are equal therefore . assuming the sides equal to x we have 2x square=128 x square= 64 x = -+8 but length is always positive. therefore other two sides = x= 8

a square area will be 8x8=64. Formula is a2 + b2 = c2. In other words the square root of (8x8 + 8x8) 128 which is 11.31371

root 225 is 15, that is the only one. The rest are not even squares

Area of the right isosceles triangle: 0.5*16*16 = 128 square units

128 is a square number 128 is a square number

The square root of the square root of the square root of something is called the 8th root. The 8th root of pi is approximately 1.15383506784999.

The square root of the square root of 2

If you mean 128 then it is 2

We use the property of square roots that says the square root of (ab)=square root (a) multiplied by square root of b So square root (4x)=square root (4) mutiplies by square root of x =2(square root (x)) 2sqrt(x)

square root 2 times square root 3 times square root 8

-1281/2 = -11/2 * 1281/2 = i * 1281/2 = i * 641/2 * 21/2 = i * 8 * 21/2Short of now calculating the value and writing this as a multiple of i this is as simplified as it can be.The square root of -128 = 8i * 21/2(note: x1/2 means "the square root of x").

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