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The square root of 128 is not an irrational number; it can be simplified. Specifically, (\sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2}). Since (\sqrt{2}) is irrational, (\sqrt{128}) is also irrational.

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AnswerBot

6h ago

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