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Q: What is the square root of 17 to the power of 2?

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The square root of 2 to the power of 10 = 32

square root of 9 = 3 but 2, 17 and 23 are irrational numbers

The idea is to find a perfect square among its factors, such as two square, three square, etc. In this case, the square root of 68, root(68), equals root(4 x 17) = root(4) x root(17) = 2 root(17).

2 square root 17

Two to the power 8 (28) is 256 The square root of 256 is 16. When you take the square root of a number raised to a power y, divide that power by 2 (y/2) and that gives the square root. So the square root of 28 = 28/2 = 24 = 16

if youre trying to say √17 * √2 then that's the same as √(17*2). when multiplying two square roots you can multiply them together then take the square root. so it's √34 or 5.83095

16 to the power (1/2) is the same as the square root of 16 - that is, 4.16 to the power (1/2) is the same as the square root of 16 - that is, 4.16 to the power (1/2) is the same as the square root of 16 - that is, 4.16 to the power (1/2) is the same as the square root of 16 - that is, 4.

12... 12 to the power 2 is 144. the square root of 144 is 12

The square root of 2 raised to the fifth power equals 5.65685424949

2 times the square root of 17

2

36

A square root is a number raised to the exponent (power) 1/2.

The square root of 17 lies between the integers 4 and 5.

2

15.

It is: 1/2

ok lets let x=4. The square root of 4 to the 2nd power + 4= 8. The square root and power of 2 cancel out? Is that what you mean?

Something to the power of 1/2 is the same as the square root of a number so 25 to the power of a 1/2 = the square root of 25 = 5

The square root of the square root of 2

PLUS 2

You divide the exponent by 2 The square root of a number is that number to the 1/2 power So for examle square root of x cubed (x^3) is x^3 to the half power =x^3/2 (x to the 3/2 power)

There are two square roots of i: (-1/square root 2)(1+i) and (1/square root 2)(1+i) so these are i to the one half power. Now to find -i to the one half power, multiply either of these by i, since i2 is -1. So (-i/square root 2)(1+i) and (i/square root 2)(1+i) are the square roots of -i. Verify this by direct multiplication.

The square root of 2 plus the square root of 2 is equal to twice the square root of 2, therefore the correct answer is: 2(√2) or √8

2.5