ok lets let x=4. The square root of 4 to the 2nd power + 4= 8. The square root and power of 2 cancel out? Is that what you mean?
4
There is no "8 square root" of something. You can calculate the square root, or the 8th. root, of something.
The square root of x to the 8th power is x to the 4th power. This is because when you take the square root of a number raised to an exponent, you divide the exponent by 2. In this case, 8 divided by 2 is 4, so the square root of x to the 8th power is x to the 4th power.
4
The square root is the same as raising to the one-half power x tot he power of 8 tot he power of 8 to the power of one-half is x to the 32 power (x to the 8x8x1/2)
The square root of 8 is 2 times the square root of 2 sqrt(8) = 2 x sqrt(2)
ok lets let x=4. The square root of 4 to the 2nd power + 4= 8. The square root and power of 2 cancel out? Is that what you mean?
square root 2 times square root 3 times square root 8
The square root of 8 is 2 multiplied by the square root of 2
To get the square root of 8, you have to multiply the root of 2 and the root of 4. The root of 4 then simplifies to 2, so the square root of 8 equals 2 times the square root of 2.
No, id does not.
4
There is no "8 square root" of something. You can calculate the square root, or the 8th. root, of something.
The square root of 64 is the number that, when squared (multiplied by itself), equals 64. The square root of 64 is 8 because 8 x 8 = 64. The square root is also expressed as the number raised to the one-half power (64^(1/2)=8).
8 divided by 2 = 4 4 to the second power (42) = 16 The square root of 16 = 4
Sq root of 2 * sq root of 8 = 1.414 * 2.828 = 3.998792