Putting the data into excel, the std dev for the sample is 6.20
Mean: 26.33 Median: 29.5 Mode: 10, 35 Standard Deviation: 14.1515 Standard Error: 5.7773
It is the sample mean age of 21.7.
15.72683482 is the standard deviation for that set of numbers.
8.919280881 is the standard deviation for those numbers.
The mean absolute deviation (from the mean) is 4.75
38 cal
Pacific Standard time. Today is October 25, 2010 at 11:35 am.
35 in standard form is: 3.5 × 101
It means that all of the ten numbers are 15!Standard deviation tells you how spread out the data is from the mean value. Or in other words, it tells you how far the numbers in your data are away from the mean value.If the standard deviation is a high number, it means the data is largely spread out and that there are big differences in the data. The numbers in the data would be quite far from each other. For example, if you had data like: 8, 35, 13, 47, 22, 64, this would probably mean that you'll get a high standard deviation because each of the numbers are very spread out.On the other hand, if the standard deviation is small, it tells you that the numbers in the data are quite close together and that there is only a small difference between the numbers in the data. For example, if you had data like: 19, 25, 20, 22, 23, 18, this would probably mean that you'll get a low standard deviation because each of the numbers aren't that spread outIn the scenario you've given, the standard deviation is ZERO. This means that there is no spread or variation AT ALL with the numbers in your data. This means every single number in the data is the same.Since your mean is 15 and every number in your data is the same, that means that all the ten numbers in your data have to be 15!Hope that makes sense.Jamz159
An x value that is smaller than the mean cannot have a positive z score.
35% of 25= 35% * 25= 0.35 * 25= 8.75
Standard deviation = sqrt(variance) Variance = E[X2] - E[X]2 E[X] = sum(X)/n = 35/9, so E[X]2 = 1225/81 E[X2] = sum(X2)/n = 189/9 = 1701/81 Variance = 476/81 Standard deviation = sqrt(476/81) ~ 2.42