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What is KI plus Cl2?
KI plus Cl2 undergoes a redox reaction to form KCl and I2. The chlorine (Cl2) is reduced to chloride ions (Cl-) and the iodide ions (I-) are oxidized to form elemental iodine (I2).
What kind of reaction is represented by 2k plus I 2?
The reaction represented by 2K + I2 is a combination or synthesis reaction, where potassium (K) and iodine (I2) combine to form potassium iodide (KI).
What reaction is Br2 plus 2KI equals 2KBr plus I2?
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
What type of reaction is H2 plus I2 equals 2HI?
This is a combination reaction, where two or more substances combine to form a single product. In this case, hydrogen gas (H2) and iodine gas (I2) react to form hydrogen iodide gas (2HI).
What is the balanced chemical equation for KI plus Cl2 equals KCl plus I2?
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
Solve this equation x2 - 8x plus 17 equals 0?
(4 ± i2) where i2 = -1
Express the square root-48 plus 35 plus square root 25 plus square root-27 in simplest a plus bi form?
√-48 + 35 + √ 25 + √-27 = √[(i2)(16)(3)] + 35 + 5 + √[(i2)(9)(3)] = 4i√3 + 38 + 9i√3 = 38 + (13√3)i
What type of reaction is Cl2 plus 2KI- 2KCl plus I2?
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
Combination reaction of NA plus I2?
When sodium metal is combined with iodine gas, an oxidation-reduction reaction occurs. Sodium loses and electron to form the sodium cation, and iodide gains an electron to form iodide. The resulting compound is NaI.
What is the balanced formula equation for chlorine plus potassium iodide equals potassium chloride plus iodine?
Cl2 + 2KI → 2KCl + I2
What is the symbol for iodine gas?
I2(g) is the symbol for iodine in its standard state (including its state symbol.)
H2g plus I2g 2hIg has keq equals 0.15 at a certain temperature if h2 equals 0.01 I2 equals 0.02 and hI equals 0.03 what is true about this reaction?
HI will be consumed. The reaction will proceed to the left. More I2 will form.
