It is 2I + 1.
The coefficient is put before the variable.
2Na+I2-->2NaI
I2
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
(4 ± i2) where i2 = -1
√-48 + 35 + √ 25 + √-27 = √[(i2)(16)(3)] + 35 + 5 + √[(i2)(9)(3)] = 4i√3 + 38 + 9i√3 = 38 + (13√3)i
This is a combination or synthesis reaction. 2 atoms of K (potassium) combine with a diatomic molecule I2 (iodine) to form two molecules of KI (potassium iodide).
Redox reaction.
HI will be consumed. The reaction will proceed to the left. More I2 will form.
4
2Mg + I2 ----> 2MgI
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
Br2 + 2NaI -> 2NaBr + I2