Best Answer

x² + y² - 4x + y - 1 = 0

( x² - 4x ) + ( y² + y ) = 1

( x² - 4x + 4 ) + [ y² + y + (1/4) ] = 1 + 4 + (1/4)

( x - 2 )² + [ y + (1/2) ]² = [ √(21) / 2 ]²

This equation represents a Circle with

Centre ≡ ( 2, -1/2 ) and Radius = √(21) / 2.

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Q: What is the standard form of x2 plus y2-4x plus y-1 equals 0?

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