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You need to be more accurate and precise in submitting problems of this nature. Regardless, I think I have it figured out. The functions
Y2 = 4X
Y = 2X
To find area here you need bounds. The graph admits of only these bounds; 0 to 1. Y2 = 4X is the top function.
Rewrite.
Y2 = 4X
Y = sqrt(4X)
Y = 4X 1/2
------------------integrate
int( 4X 1/2 - 2X) dx
= (8/3)X 3/2 - X2
----------------------------------insert bounds
(8/3)(1) 3/2 - (0)2
= 8/3
======the area between these functions
What else can I help you with?
How do you find the area between the curves y equals 1 divide by x and y equals sin x in the region x greater than 0 but smaller than pi?
Undefined: You cannot divide by zero
How do you calculate the area under a curve?
Generally. Area = the definite integration from a to b [ f(x) - g(X)]dx Say you have two functions( y = e^x and y = x) and you want to find the area between them on an interval ( say 1 to 3 ) So you set the top function(e^x) subtracting the bottom function(x) and integrate them, Insert the values, b - a in the integrated functions and get the value of the area.
What does integrategration mean?
Integration refers to the process of combining different parts into a unified whole. In mathematics, it involves finding the integral of a function, which represents the accumulation of quantities, such as area under a curve. In broader contexts, integration can also imply the merging of diverse groups, ideas, or systems to create harmony and efficiency.
Find the exact value of the area under the first arch of fx x sinx The first arch is between x 0 and the first positive x-intercept?
First, find the upper limit of integration by setting xsin(x)=0. It should be pi. Then use integration by parts to integrate xsin(x) from 0 to pi u=x dv=sinx dx du=dx v=-cosx evaluate the -xcosx+sinx from 0 to pi the answer is pi ps webassign sucks
The area of the region enclosed by the graph of y 2 x2 1 and the line y 2 x 5 is what?
∣∣2−1 . -6 + 15 = 9 To calculate the area between the curves y = 2 x2 + 1 and y = 2 x + 5, we must evaluate the integral ∫ab(2x+5)−(2x2+1)dx . To determine which values to use for a and b as the limits of the integral, we calculate the x values where the two curves intersect. Solve 2 x2 + 1 = 2 x + 5 by factoring to get x = 2 and x = -1. Set a = -1, b = 2. The enclosed area, A , is therefore given by the equation A=∫2−1(2x+5)−(2x2+1)dx=∫2−1−2x2+2x+2x+4 dx=[−2x33+x2+4x]
What is the area between 2 specific boundaries?
To find the area between two specific boundaries, you typically need to define the boundaries mathematically, such as through equations of curves or lines. Once the boundaries are established, you can calculate the area using integration if they are functions, or by applying geometric formulas if they are shapes. The area is then determined by evaluating the integral or formula between the defined limits. If you provide specific boundaries, I can assist further with the calculation.
Can area enclosed between 2 curves be zero?
no
The area between 2 specific boundaries?
The area between two specific boundaries refers to the space that lies between defined limits, which could be lines, curves, or other geometric figures. This area can be calculated using integration in calculus, where the boundaries are represented as functions or equations. Understanding this concept is crucial in various fields, such as physics, engineering, and economics, where it helps in determining quantities like total distance, volume, or profit. By identifying the specific boundaries, one can accurately assess the magnitude of the area in question.
What is the difference between integration and derivation?
Integration results in an equation which gives the area under the original equation between the bounds. Derivation results in an equation which gives the slope of the original line at any point.
Different types of intergration?
Integration can be categorized into several types, including definite and indefinite integration. Definite integration calculates the area under a curve between two specific points, while indefinite integration finds the antiderivative of a function without limits. Other forms include numerical integration, which approximates the value of integrals using algorithms, and multiple integration, which extends the concept to functions of several variables. Each type serves different purposes in mathematics, physics, and engineering applications.
What are the Applications of differentiation and integration?
Shipwrecks occured because the ship was not where the captain thought it should be. There was not a good enough understanding of how the Earth, stars and planets moved with respect to each other.Calculus (differentiation and integration) was developed to improve this understanding.Differentiation and integration can help us solve many types of real-world problems.We use the derivative to determine the maximum and minimum values of particular functions (e.g. cost, strength, amount of material used in a building, profit, loss, etc.).Derivatives are met in many engineering and science problems, especially when modelling the behaviour of moving objects.INTEGRATION:1. Applications of the Indefinite Integral shows how to find displacement (from velocity) and velocity (from acceleration) using the indefinite integral. There are also some electronics applications.In primary school, we learned how to find areas of shapes with straight sides (e.g. area of a triangle or rectangle). But how do you find areas when the sides are curved? e.g.2. Area Under a Curve and3. Area Between 2 Curves . Answer is by Integration.4. Volume of Solid of Revolution explains how to use integration to find the volume of an object with curved sides, e.g. wine barrels.5. Centroid of an Area means the centre of mass. We see how to use integration to find the centroid of an area with curved sides.6. Moments of Inertia explains how to find the resistance of a rotating body. We use integration when the shape has curved sides.7. Work by a Variable Force shows how to find the work done on an object when the force is not constant.8. Electric Charges have a force between them that varies depending on the amount of charge and the distance between the charges. We use integration to calculate the work done when charges are separated.9. Average Value of a curve can be calculated using integration.
How do you calculate the surface area or volume of each shape?
we can use integration.- multiple integration.
Why should isotherms be smoothly drawn curves?
Isotherms should be smoothly drawn curves because they represent continuous temperature distributions across a given area, reflecting the gradual change in temperature rather than abrupt shifts. Smooth curves help to accurately depict the relationships between temperature and spatial variables, allowing for better interpretation of thermal gradients. Additionally, using smooth lines aids in visual clarity and enhances the readability of temperature data on maps or graphs.
How do you find the area between the curves y equals 1 divide by x and y equals sin x in the region x greater than 0 but smaller than pi?
Undefined: You cannot divide by zero
How can one determine the economic surplus on a graph?
To determine the economic surplus on a graph, calculate the area between the supply and demand curves up to the equilibrium point. This area represents the total economic surplus in the market.
How do fractals relate to math?
Fractals are a special kind of curve. They are space filling curves and have dimensions that are between those of a line (D = 1) and an area (D = 2).
What is the area you want to hit to get a strike?
That area is called the 'pocket'. For a left handed bowler that curves the ball from the left side, the pocket is between the #s 1 and 2 pins. For a right handed bowler that curves the ball from the right side, the pocket is between the #s 1 and 3 pins. For a bowler of either hand that rolls the ball straight, either the 1/2 or the 1/3 pockets will do good.
