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How do you find the area between the curves y24x and y2x using integration?
Wiki User
∙ 11y ago
You need to be more accurate and precise in submitting problems of this nature. Regardless, I think I have it figured out. The functions
Y2 = 4X
Y = 2X
To find area here you need bounds. The graph admits of only these bounds; 0 to 1. Y2 = 4X is the top function.
Rewrite.
Y2 = 4X
Y = sqrt(4X)
Y = 4X 1/2
------------------integrate
int( 4X 1/2 - 2X) dx
= (8/3)X 3/2 - X2
----------------------------------insert bounds
(8/3)(1) 3/2 - (0)2
= 8/3
======the area between these functions
Wiki User
∙ 11y ago
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