1765
8,749.
99 hundreds, 10 tens,4 ones
7,000,000,350 :)
To convert 11 hundreds, 12 tens, and 6 ones into standard form, you first calculate the values: 11 hundreds is 1100, 12 tens is 120, and 6 ones is 6. Adding these together: 1100 + 120 + 6 equals 1226. Therefore, in standard form, it is written as 1226.
5,033
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
3 tens, 2 ones, 6 thousandths (in standard form)
To write 387 in standard notation, you simply write the number as it is: 387. Standard notation is the usual way we write numbers using digits, with each digit representing a different place value. In the number 387, the 3 is in the hundreds place, the 8 is in the tens place, and the 7 is in the ones place.
254 - has 2 hundreds, 5 tens, and 4 ones
Your correct answer is hundreds place because you have your ones period like ones tens hundreds same with the thousands period ones tens hundreds.
15 638 can be made with 1 ten, 5 ones, 6 hundreds, 3 tens, and 8 ones; 1 ten, 8 ones, 6 hundreds, 3 tens, and 5 ones; or 6 ones, 5 hundreds, 3 tens, 8 ones, and 1 ten.
987 in expanded notation as an addition expression would be 900 + 80 + 7. This is because each digit is represented by its place value, with the hundreds digit in the hundreds place, the tens digit in the tens place, and the ones digit in the ones place. Adding these together gives us 987.